(x^2-4x+2)+(y^2+6y+9)=16

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Solution for (x^2-4x+2)+(y^2+6y+9)=16 equation: 


Simplifying
(x2 + -4x + 2) + (y2 + 6y + 9) = 16

Reorder the terms:
(2 + -4x + x2) + (y2 + 6y + 9) = 16

Remove parenthesis around (2 + -4x + x2)
2 + -4x + x2 + (y2 + 6y + 9) = 16

Reorder the terms:
2 + -4x + x2 + (9 + 6y + y2) = 16

Remove parenthesis around (9 + 6y + y2)
2 + -4x + x2 + 9 + 6y + y2 = 16

Reorder the terms:
2 + 9 + -4x + x2 + 6y + y2 = 16

Combine like terms: 2 + 9 = 11
11 + -4x + x2 + 6y + y2 = 16

Solving
11 + -4x + x2 + 6y + y2 = 16

Solving for variable 'x'.

Reorder the terms:
11 + -16 + -4x + x2 + 6y + y2 = 16 + -16

Combine like terms: 11 + -16 = -5
-5 + -4x + x2 + 6y + y2 = 16 + -16

Combine like terms: 16 + -16 = 0
-5 + -4x + x2 + 6y + y2 = 0

The solution to this equation could not be determined.

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